坐标系O’相对于O以速度v沿x轴正方向匀速运动,当坐标重合时:
\( (x=0,x’=0,t=0,t’=0) \),
当O’坐标系原点走到O坐标系的\(x_0\)位置,然后停止,
此时O坐标系看来:
\( x=x_0,t=x_0/v,x’=0\),
\(t’=\gamma(t-xv/c^2)=\frac{x_0}{v\gamma} \)
即:
\( (x_1,x’_1,t_1,t_1’)=(x_0,0,\frac{x_0}{v},\frac{1}{\gamma}\frac{x_0}{v}) \)
要折返,初始坐标为:
\( x=x_0, x’=0, t=0, t’=0 \)
回来时(相对速度变成-v):
\( \Delta x’=\gamma(\Delta x+x_0+v\Delta t) \)
\( \Delta t’=\gamma(\Delta t+(\Delta x+x_0) v/c^2) \)
\( \Delta x+x_0=\gamma(\Delta x’-v\Delta t’) \)
则会得到:
当认为\((x=0)\)时,
\( \Delta x=-x_0, \Delta t=x_0/v \),
\( \Delta x’ =\gamma(v\Delta t)=\gamma x_0 \)
\( \Delta t’ =\gamma t =\gamma x_0/v \)
即:\( (x_2,x’_2,t_2,t_2’)=(0,\gamma x_0, \frac{x_0}{v},\frac{\gamma x_0}{v}) \)
...